NCERT Solutions For Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2

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Textbook	NCERT
Board	CBSE
Category	NCERT Solutions
Class	Class 8
Subject	Maths
Chapter	Chapter 6
Exercise	Class 8 Chapter 6 Squares and Square Roots Exercise 6.2
Number of Questions Solved	6

NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2

NCERT TEXTBOOK EXERCISES

Question 1. Find the square of the following numbers:

(i) 32
(ii) 35
(iii) 86
(iv) 93
(v) 71
(vi) 46

Solution.

(i) 32
32 = 30 + 2
Therefore, 32² = (30+2)²
= 30 (30 + 2) + 2 (30 + 2)
= 900 + 60 + 60 + 4
= 1024

(ii) 35
35 = 30 + 5
Therefore, 35² = (30+5)²
= 30 (30 + 5) + 5 (30 + 5)
= 900 + 150 + 150 + 25
= 1225

(iii) 86
86 = 80 + 6
Therefore, 86²= (80+6)²
= 80 (80 + 6) + 6 (80 + 6)
= 6400 + 480 + 480 + 36
= 7396

(iv) 93
93 = 90 + 3
Therefore, 90²= (90+3)²
= 90 (90 + 3) + 3 (90 + 3)
= 8100 + 270 + 270 + 9
= 8649

(v) 71
71 = 70 + 1
Therefore, 70²= (70+1)²
= 70 (70 + 1) + 1 (70 + 1)
= 4900 + 70 + 70 + 1
= 5041

(vi) 46
46 = 40 + 6
Therefore, 40²= (40+6)²
= 40 (40 + 6) + 6 (40 + 6)
= 1600 + 240 + 240 + 36
= 2116

Question 2. Write a Pythagorean triplet whose one number is

(i) 6
(ii) 14
(iii) 16
(iv) 18

Solution.

(i) 6
Let 2m = 6
⇒ $m=\frac { 6 }{ 2 } =3$

(ii) 14
Let 2m = 14

(iii) 16
Let 2m = 16

(iv) 18
Let 2m = 18

NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Exercise 6.2 PDF

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Class 8 Maths Chapter 6 Squares and Square Roots

• Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.1
• Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2
• Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.3
• Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.4