NCERT Solutions For Class 8 Maths Chapter 4 Practical Geometry Ex 4.2
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| Textbook | NCERT |
| Board | CBSE |
| Category | NCERT Solutions |
| Class | Class 8 |
| Subject | Maths |
| Chapter | Chapter 4 |
| Exercise | Class 8 Chapter 4 Practical Geometry Exercise 4.2 |
| Number of Questions Solved | 6 |
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2
NCERT TEXTBOOK EXERCISES
Question 1. Construct the following quadrilaterals:
(i) Quadrilateral LIFT
LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
(ii) Quadrilateral GOLD
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm
(iii) Rhombus BEND
BN – 5.6 cm
DE = 6.5 cm
Solution.
(i) Steps of Construction
- Draw LI = 4 cm.
- With L as center and radius LT = 2.5 cm, draw an arc.
- With I as center and radius, IT = 4 cm, draw another arc to intersect the arc drawn in step 2 at T.
- With I as center and radius IF = 3 cm, draw an arc.
- With L as center and radius LF = 4.5 cm, draw another arc to intersect the arc drawn in step 4 at F.
- Join IF, FT, TL, LF and IT.
Then, LIFT is the required quadrilateral.
(ii) Steps of Construction
- Draw LD = 5 cm.
- With L as center and radius LG = 6 cm, draw an arc.
- With D as center and radius DG = 6 cm, draw another arc to intersect the arc drawn in step 2 at G.
- With L as center and radius LO = 7.5 cm, draw an arc.
- With D as center and radius DO = 10 cm, draw another arc to intersect the arc drawn in step 4 at O.
- Join DG, GO, OL, LG and DO.
Then GOLD is the required quadrilateral.
(iii) Steps of Construction
- Draw DE = 6.5 cm.
- Draw perpendicular bisector PQ of DE so as to intersect DE at M. Then M is the mid-point of DE.
- With M as centre and radius
$=\frac { 1 }{ 2 } \times \left( 5.6 \right) =2.8 cm$
opposite sides of DE to intersect MP at N and MQ at B.
- Join DN, NE, EB, and BD.
Then, BEND is the required rhombus.
NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Exercise 4.2 PDF
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