# NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.5

Here, Below you all know about NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.5 Question Answer. I know many of you confuse about finding this Chapter 2 Linear Equations in One Variable Ex 2.5 Of Class 8 NCERT Solutions. So, Read the full post below and get your solutions.

## NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.5

NCERT TEXTBOOK EXERCISES

Question 1. Solve the following linear equations:

1. $\frac { x }{ 2 } -\frac { 1 }{ 5 } =\frac { x }{ 3 } +\frac { 1 }{ 4 }$
2. $\frac { n }{ 2 } -\frac { 3n }{ 4 } +\frac { 5n }{ 6 } =21$
3. $x+7-\frac { 8x }{ 3 } =\frac { 17 }{ 6 } -\frac { 5x }{ 2 }$
4. $\frac { x-5 }{ 3 } =\frac { x-3 }{ 5 }$
5. $\frac { 3t-2 }{ 4 } -\frac { 2t+3 }{ 3 } =\frac { 2 }{ 3 } -t$
6. $m-\frac { m-1 }{ 2 } =1-\frac { m-2 }{ 3 }$

Solution.

1. $\frac { x }{ 2 } -\frac { 1 }{ 5 } =\frac { x }{ 3 } +\frac { 1 }{ 4 }$

2. $\frac { n }{ 2 } -\frac { 3n }{ 4 } +\frac { 5n }{ 6 } =21$

3. $x+7-\frac { 8x }{ 3 } =\frac { 17 }{ 6 } -\frac { 5x }{ 2 }$

4. $\frac { x-5 }{ 3 } =\frac { x-3 }{ 5 }$

5. $\frac { 3t-2 }{ 4 } -\frac { 2t+3 }{ 3 } =\frac { 2 }{ 3 } -t$

6. $m-\frac { m-1 }{ 2 } =1-\frac { m-2 }{ 3 }$
We have $m-\frac { m-1 }{ 2 } =1-\frac { m-2 }{ 3 }$

Question 2. Simplify and solve the following linear equations:

7. 3(t-3)=5(2t+1)
8. 15(y-4)-2(y-9)+5 (y+6) = 0
9. 3(5z-7)-2 (9z-11)=4 (8z-13)-17
10. 0.25(4f-3) = 0.05 (10f-9).

Solution.

7. 3(t-3)=5(2t+1)

8. 15(y-4)-2(y-9)+5 (y+6) = 0

9. 3(5z-7)-2 (9z-11)=4 (8z-13)-17

10. 0.25(4f-3) = 0.05 (10f-9)

## NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Exercise 2.5 PDF

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