# NCERT Solutions For Class 8 Maths Chapter 11 Mensuration Ex 11.2

Here, Below you all know about NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.2 Question Answer. I know many of you confuse about finding this Chapter 11 Mensuration Ex 11.2 Of Class 8 NCERT Solutions. So, Read the full post below and get your solutions.

## NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.2

NCERT TEXTBOOK EXERCISES

Question 1. The shape of the top surface of a table is a trapezium. Find its area, if its parallel sides are 1 m and 1.2 man the d perpendicular distance between them is 0.8 m.

Solution.

Area of the top surface of the table

= $\frac { 1 }{ 2 } h(a+b)$
= $\frac { 1 }{ 2 } \times 0.8\times (1.2+1)$
= 0.88m2

Question 2. The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the another parallel side.

Solution.

Area of trapezium
= $\frac { 1 }{ 2 } h(a+b)$

⇒ $34=\frac { 1 }{ 2 } \times 4(10+b)$
⇒ $34=2\times (10+b)$
⇒ 10+b=34/2
⇒ 10 + b=17
⇒ b = 17 – 10
⇒ b = 7 cm
Hence, the length of another parallel side is 7 cm.

Question 3. Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC

Solution.

Fence of the trapezium shaped field ABCD = 120 m
⇒ AB + BC + CD + DA = 120
⇒ AB + 48 + 17 + 40 = 120
⇒ AB + 105 = 120
⇒ AB = 120 – 105
⇒ AB = 15 m
∴ Area of the field
= $\frac { (BC+AD)\times AB }{ 2 }$
= $\frac { (48+40)\times 16 }{ 2 }$ = 660 m2

Question 4. The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Solution.

Area of the field
= $\frac { 1 }{ 2 } d({ h }{ 1 }+{ h }{ 2 })$
= $\frac { 24\times (8+13) }{ 2 }$ = $\frac { 24\times 21 }{ 2 }$
= 12 x 21 = 252m2

Question 5. The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.

Solution.

Area of the rhombus

= 1/2×d1×d2
= 1/2×7.5×12
= 45 m2

Question 6. Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.

Solution.

Area of the rhombus
= base (b) x altitude (h) = 5
= 5 x 4.8 = 24 cm2

Question 7. The floor of a building consists of 3,000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m2 is ₹ 4.

Solution.

Area of a tile

Question 8. Mohan wants to buy a trapezium shaped field. Its side along the river is parallel to and twice the side along the road. If the area of this field is 10,500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.

Solution.

Let the length of the side along the road be x m. Then, the length of the side along the river is 2x m.
Area of the field = 10,500 square metres

Question 9. Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.

Solution.

Area of the octagonal surface

Question 10. There is a pentagonal shaped park as shown in the figure. For finding its area Jyoti and Kavita divided it in two different ways.

Find the area of this park using both ways. Can you suggest some other way of finding its area ?

Solution.

Question 11. Diagram of the adjacent picture frame has outer dimensions = 24 cm x 28 cm and inner dimensions 16 cm x 20 cm. Find the area of each section of the frame, if the width of each section the same.

Solution.

## NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.2 PDF

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