# NCERT Solutions For Class 8 Maths Chapter 10 Visualising Solid Shapes Ex 10.3

Here, Below you all know about NCERT Solutions for Class 8 Maths Chapter 10 Visualising Solid Shapes Ex 10.3 Question Answer. I know many of you confuse about finding this Chapter 10 Visualising Solid Shapes Ex 10.3 Of Class 8 NCERT Solutions. So, Read the full post below and get your solutions.

Textbook | NCERT |

Board | CBSE |

Category | NCERT Solutions |

Class | Class 8 |

Subject | Maths |

Chapter | Chapter 10 |

Exercise | Class 8 Chapter 10 Visualising Solid Shapes Exercise 10.3 |

Number of Questions Solved | 8 |

## NCERT Solutions for Class 8 Maths Chapter 10 Visualising Solid Shapes Ex 10.3

**NCERT TEXTBOOK EXERCISES**

**Question 1. Can a polyhedron have for its faces**

**(i)** 3 triangles?**(ii)** 4 triangles?**(iii)** a square and four triangles?

**Solution.**

**(i)** No**(ii)** Yes**(iii)** Yes

**Question 2. Is it possible to have a polyhedron with any given number of faces? (Hint: Think of a pyramid).**

**Solution.**

Possible, only if the number of faces is greater than or equal to 4.

**Question 3. Which are prisms among the following?**

**Solution.**

We know that a prism is a polyhedron whose base and top faces are congruent and parallel and other (lateral) faces are parallelograms in shape. So, only (ii) and (iv) are prisms.

**Question 4.****(i)** How are prisms and cylinders alike?**(ii)** How are pyramids and cones alike?

**Solution.**

**(i)** The prisms and cylinder, both, have their base and top faces as congruent and parallel to each other. Also, a prism becomes a cylinder as the number of sides of its base becomes larger and larger.

**(ii)** The pyramids and cones are alike in the sense that their lateral faces meet at a point (called vertex). Also, a pyramid becomes a cone as the number of sides of its base becomes larger and larger.

**Question 5. Is a square prism same as a cube ? Explain.**

**Solution.**

No; not always as it can be a cuboid also.

**Question 6. Verify Euler’s formula for these solids**

**Solution.**

**(i)**F = 7

V= 10

E = 15

F + V = 7 + 10 = 17

E + 2 = 15 + 2 = 17

So, F + V = E + 2

Hence, Euler’s Formula is verified,

**(ii)**

F = 9

V = 9

E = 16

F + V = 9 + 9 = 18

E + 2 = 16 + 2 = 18

So, F + V = E + 2

Hence, Euler’s Formula is verified

**Question 7. Using Euler’s formula find the unknown.**

**Solution.**

**(i)**

F + V = E + 2

⇒ F + 6 = 12 + 2

⇒ F + 6 = 14

⇒ F = 14 – 6 = 8

**(ii)**

F + V = E + 2

⇒ 5 + V = 9 + 2

⇒ 5 + V = 11

⇒ V= 11-5 = 6

**(iii)**

F + V = E + 2

⇒ 20 + 12 = E + 2

⇒ 32 = E + 2

⇒ E = 32 – 2

⇒ E = 30

**Question 8. Can a polyhedron have 10 faces, 20 edges, and 15 vertices?**

**Solution.**

Here F = 10

E = 20

V= 15

So, F + V = 10 + 15 = 25

E + 2 = 20 + 2 = 22

∵ F + V ≠ E + 2

∴ Such a polyhedron is not possible.

## NCERT Solutions for Class 8 Maths Chapter 10 Visualising Solid Shapes Exercise 10.3 PDF

For NCERT Solutions for Class 8 Maths Chapter 10 Visualising Solid Shapes Ex 10.3, you may click on the link below and get your NCERT Solutions for Class 8 Maths Chapter 10 Visualising Solid Shapes Exercise pdf file.

Finally, You all know about NCERT Solutions for Class 8 Maths Chapter 10 Visualising Solid Shapes Ex 10.3. If you have any questions, then comment below and share this post with others.