NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2
Here, below you all know about NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 Question Answer. I know many of you confuse about finding this Chapter 11 Perimeter and Area Ex 11.2 Of Class 7 NCERT Solutions. So, Read the full post below and get your solutions.
| Textbook | NCERT |
| Board | CBSE |
| Category | NCERT Solutions |
| Class | Class 7 |
| Subject | Maths |
| Chapter | Chapter 11 |
| Chapter Name | Perimeter and Area Ex 11.2 |
| Number of Questions Solved | 6 |
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2
NCERT TEXTBOOK EXERCISES
Question 1. Find the area of the following parallelograms:
Solution:
Question 2. Find the area of each of the following triangles:
Solution:
Question 3. Find the missing values:
Solution:
Question 4. Find the missing values:
Solution:
Question 5. PQRS is a parallelogram (in Figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find:
(a) the area of the parallelogram PQRS
(b) QN, if PS = 8 cm.
Solution:
(a) Area of the parallelogram PQRS = base × height = SR × QM = 12 × 7.6 cm2 = 91.2 cm2
(b) Area of the parallelogram PQRS = base × height = PS × QN
⇒ 91.2 = 8 × QN
⇒ QN = 912/8 cm
⇒ QN = 11.4 cm.
Question 6. DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (in Figure). If the area of a parallelogram is 1470 cm2, AB = 35 cm, and AD = 49 cm, find the length of BM and DL.
Solution:
Question 7. ∆ ABC is right-angled at A (in Figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ ABC. Also, find the length of AD.
Solution:
Question 8. ∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height of AD from A to BC is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?
Solution:
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 PDF
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