# NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5

Here, below you all know about NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 Question Answer. I know many of you confuse about finding this Chapter 10 Practical Geometry Ex 10.5 Of Class 7 NCERT Solutions. So, Read the full post below and get your solutions.

## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5

NCERT TEXTBOOK EXERCISES

Question 1. Construct the right-angled ∆ PQR where m ∠Q = 90°, QR = 8 cm and PR = 10 cm.

Solution:

Steps of Construction:

1. Draw QR of length 8 cm.
2. At Q, draw QX ⊥ QR.
3. With R as centre, draw an arc of radius 10 cm.
4. Mark the meeting point of these two as P.

∆ PQR is now obtained.

Question 2. Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

Solution:

Steps of Construction

1. Draw QR of length 4 cm.
2. At Q, draw QX ⊥ QR.
3. With R as centre, draw an arc of radius 6 cm.
4. Mark the meeting point of arc and QX as P.

∆ PQR is now obtained.

Question 3. Construct an isosceles right-angled triangle ABC where m ∠ACB = 90° and AC = 6 cm.

Solution:

Steps of Construction

1. Draw AC of length 6 cm.
2. At C, draw CX ⊥ CA.
3. With C as centre, draw an arc of radius 6 cm to intersect CX at B.
4. Join AB. ∆ACB is now obtained.

## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 PDF

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