NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5
Here, below you all know about NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 Question Answer. I know many of you confuse about finding this Chapter 10 Practical Geometry Ex 10.5 Of Class 7 NCERT Solutions. So, Read the full post below and get your solutions.
| Textbook | NCERT |
| Board | CBSE |
| Category | NCERT Solutions |
| Class | Class 7 |
| Subject | Maths |
| Chapter | Chapter 10 |
| Chapter Name | Practical Geometry Ex 10.5 |
| Number of Questions Solved | 3 |
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5
NCERT TEXTBOOK EXERCISES
Question 1. Construct the right-angled ∆ PQR where m ∠Q = 90°, QR = 8 cm and PR = 10 cm.
Solution:
Steps of Construction:
- Draw QR of length 8 cm.
- At Q, draw QX ⊥ QR.
- With R as centre, draw an arc of radius 10 cm.
- Mark the meeting point of these two as P.
∆ PQR is now obtained.
Question 2. Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.
Solution:
Steps of Construction
- Draw QR of length 4 cm.
- At Q, draw QX ⊥ QR.
- With R as centre, draw an arc of radius 6 cm.
- Mark the meeting point of arc and QX as P.
∆ PQR is now obtained.
Question 3. Construct an isosceles right-angled triangle ABC where m ∠ACB = 90° and AC = 6 cm.
Solution:
Steps of Construction
- Draw AC of length 6 cm.
- At C, draw CX ⊥ CA.
- With C as centre, draw an arc of radius 6 cm to intersect CX at B.
- Join AB. ∆ACB is now obtained.
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 PDF
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