NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3
Here, below you all know about NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 Question Answer. I know many of you confuse about finding this Chapter 10 Practical Geometry Ex 10.3 Of Class 7 NCERT Solutions. So, Read the full post below and get your solutions.
| Textbook | NCERT |
| Board | CBSE |
| Category | NCERT Solutions |
| Class | Class 7 |
| Subject | Maths |
| Chapter | Chapter 10 |
| Chapter Name | Practical Geometry Ex 10.3 |
| Number of Questions Solved | 3 |
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3
NCERT TEXTBOOK EXERCISES
Question 1. Construct ADEF such that DE = 5 cm, DF 3 cm, and m ∠EDF = 90°.
Solution:
Steps of Construction:
- Draw a line segment DE = 5cm.
- Draw ∠EDX = 90°.
- With centre D and radius = 3 cm, draw an arc to intersect DX at F.
- Join EF to obtain the required triangle DBF.
Question 2. Construct an isosceles triangle in which the length of each of its equal sides is 6.5 cm and the angle between them is 110°.
Solution:
Steps of Construction
- Draw a line segment QR of length 6.5 cm.
- At Q, draw QX making 110° with QR, using a protractor.
- With Q as centre, draw an arc of a radius of 6.5 cm. It cuts QX at P.
- Join PR. ∆ PQR is now obtained.
Question 3. Construct ∆ ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.
Solution:
Steps of Construction:
- Draw a line segment BC = 7.5 cm.
- Draw ∠BCX = 60°.
- With C as centre and radius = 5 cm, draw an arc intersecting CX at A.
- Join AB to obtain the required ∆ABC.
NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 PDF
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