# NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2

Here, below you all know about NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2 Question Answer. I know many of you confuse about finding this Chapter 10 Practical Geometry Ex 10.2 Of Class 7 NCERT Solutions. So, Read the full post below and get your solutions.

## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2

NCERT TEXTBOOK EXERCISES

Question 1. Construct A XYZ in which XY = 4.5 cm, YZ = 5 cm and, ZX = 6 cm.

Solution:

Steps of Construction

1. Draw a line segment YZ of length 5 cm. 2. With Y as centre, draw an arc of radius 4.5 cm.
3. With Z as centre, draw an arc of radius 6 cm,
4. Mark the point of intersection of arcs as X.
5. Join XY and XZ. ∆ XYZ is now ready.

Question 2. Construct an equilateral triangle of side 5.5 cm.

Solution:

Steps of Construction:

1. Draw a line segment BC of length 5.5 cm.
2. With B as centre, draw an arc of radius 5.5 cm. 3. With C as centre, draw an arc of radius 5.5 cm.
4. Mark the point of intersection of arcs as A.
5. Join AB and AC. Equilateral ∆ ABC is now ready.

Question 3. Draw ∆ PQR with PQ = 4 cm, QR =3.5 cm and PR = 4 cm. What type of triangle is this?

Solution:

Steps of Construction:

1. Draw a line segment QR of length 3.5 cm.
2. With Q as centre, draw an arc of radius 4 cm.
3. With R as centre, draw an arc of radius 4 cm. 4. Mark the point of intersection of arcs as P.
5. Join PQ and PR.

∵ PQ = PR
∴ ∆ PQR is isosceles.

Question 4. Construct ∆ ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

Solution:

Steps of Construction

1. Draw a line segment BC of length 6 cm. 2. With B as centre, draw an arc of radius 2.5 cm.
3. With C as centre, draw an arc of a radius of 6.5 cm.
4. Mark the point of intersection of arcs as A.
5. Join AB and AC.
6. ∆ ABC is now ready. On measurement, ∠B = 90°.

## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2 PDF

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