# NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2

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Textbook | NCERT |

Board | CBSE |

Category | NCERT Solutions |

Class | Class 6 |

Subject | Maths |

Chapter | Chapter 6 |

Chapter Name | Integers Ex 6.2 |

Number of Questions Solved | 6 |

## NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2

**NCERT TEXTBOOK EXERCISES**

**Question 1. Using number line write the integer which is:**

**(a)** 3 more than 5**(b)** 5 more than – 5**(c)** 6 less than 2**(d)** 3 less than – 2.

**Solution.**

**(a) 3 more than 5**

We start from 5 and proceed 3 steps to the right of 5 to reach 8 as shown below:

Therefore, 3 more than 5 is 8.

**(b)** **5 more than – 5**

We start from – 5 and move to the right by 5 steps and obtain 0 as shown below:

Therefore, 5 more than – 5 is 0.

**(c) 6 less than 2**We start from 2 and proceed 6 steps to the left of 2 to reach – 4 as shown below:

**(d) 3 less than – 2**We start from – 2 and move to the left by 3 steps and obtain – 5 as shown below:

Therefore, 3 less than – 2 is – 5.

Question 2.**Use number line and add the following integers:(a)** 9 +(-6)

**(b)**5+ (-11)

**(c)**(- 1) +(- 7)

**(d)**(-5)+ 10

**(e)**(-1) +(-2) + (-3)

**(f)**(-2) + 8 + (-4).

**Solution.**

**(a)** **9 +(-6)**

On the number line, we first move 9 steps to the right from 0 reaching 9 and then we move 6 steps to the left of 9 and reach 3.

Thus, 9 + (- 6) = 3.

**(b) 5 + (-11)**On the number line, we first move 5 steps to the right from 0 reaching 5 and then we move 11 steps to the left of 5 and reach – 6.

Thus, 5 + (- 11) = – 6.

**(c) (-1) + (-7)**On the number line we first move 1 step to the left of 0 reaching – 1, then we move 7 steps to the left of – 1 and reach – 8.

Thus, (- 1) + (- 7) = – 8.

**(d) (- 5) + 10**First, we move 5 steps to the left of 0 reaching – 5, then from this point, we move 10 steps to the right. We reach the point + 5.

Thus, (- 5) + 10 = 5.

**(e) (-l) + (- 2) + (-3)**First, we move 1 step to the left of 0 reaching – 1, then from this point, we move 2 steps to the left to reach – 3 and finally from – 3, we move 3 steps to the left. We reach the point – 6.

Thus, (- 1) + (- 2) + (- 3) = – 6.

**(f) (- 2) + 8 + (- 4)**First, we move 2 steps to the left of 0 reaching – 2, then from this point, we move 8 steps to the right to reach + 6 and finally from + 6 we move 4 steps to the left. We reach the point 2.

Thus, (- 2) + 8 + (- 4) = 2.

**Question 3. Add without using number line:**

**(a)** 11 + (- 7)**(b)** (- 13) + (+ 18)**(c)** (-10) + (+ 19)**(d)** (-250) + (+ 150)**(e)** (- 380) + (- 270)**(f)** (-217) + (-100).

**Solution.**

**(a) 11 + (- 7)**

11+(-7)

= 4 + 7 + (- 7)

=4+0=4

**(b) (- 13) + (+ 18)**(-13)+ (+18)

= (- 13)+ (+.13) +(+5)

= 0 + (+5) = 5

**(c) (-10) + (+ 19**)

(-10)+ (+19)

= (- 10) + (+ 10) + (+ 9)

= 0 + (+ 9) = 9=

**(d) (- 250) + (+ 150)**(- 250) + (+ 150)

= (- 100) + (- 150) + (+ 150)

= (- 100) + 0 = – 100

**(e) (- 380) + (- 270)**(- 380) + (- 270)

= -650 (/) (- 217) + (-100)

= -317.

**Question 4. Find the sum of:**

**(a)** 137 and – 354**(b)** – 52 and 52**(c)** – 312, 39 and 192

(d) – 50, – 200 and 300.

**Solution.**

**(a)** **137 and – 354**

137+ (-354)

= 137+ (- 137)+ (-217)

= 0 +(-217) =-217

**(b) – 52 and 52**

– 52 + (52)

= 0

**(c) – 312,39 and 192**

(-312)+ (39)+ (192)

= (-312)+ (231)

= (-81)+ (-231)+ (231)

= (- 81) + 0 = – 81

**(d) – 50, – 200 and 300**(-50)+ (-200)+ (300)

= (- 250) + (300)

= (- 250) + (250) + (50)

= 0 + (50) = 50.

**Question 5. Find the value of:**

(a) (-7) +(-9)+ 4 + 16

(b) (37) +(-2) +(-65) +(-8).

**Solution.**

**(a) (- 7) + (- 9) + 4 + 16**

(- 7) + (- 9) + 4 + 16

= (-16)+ 20 = (-16) +16 + 4 =0+4=4

**(b) (37) +(-2) +(-65) +(-8)**= (37)+ (75)

= (37)+ (-37)+ (-38) = 0 + (- 38)

= -38.

## NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2 PDF

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