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NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.5

Here, below you all know about NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.5 Question Answer. I know many of you confuse about finding this Chapter 5 Understanding Elementary Shapes Ex 5.5 Of Class 6 NCERT Solutions. So, Read the full post below and get your solutions.

TextbookNCERT
BoardCBSE
CategoryNCERT Solutions
ClassClass 6
SubjectMaths
ChapterChapter 5
Chapter NameUnderstanding Elementary Shapes Ex 5.5
Number of Questions Solved6
NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.5

NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.5

NCERT TEXTBOOK EXERCISES

Question 1. Which of the following are models for perpendicular lines :

(a) The adjacent edges of a table top.
(b) The lines of a railway track.
(c) The line segments forming the letter “L”.
(d) The letter V.

Solution :

(a) and (c) are models for perpendicular lines.

Question 2. Let $\overline { PQ }$ be the perpendicular to the line segment $\overline { PQ }$. Let $\vec { PQ }$ and $\overline { PQ }$ intersect in point A. What is the measure of ∠PAY?

Solution :

The measure of ∠PAY is 90°.

Question 3. There are two “set-squares ” in your box. What are the measures of the angles that are formed at their comers? Do they have any angle measure that is common?

Solution :

One is a 30° – 60° – 90° set square; the other is a 45° – 45° – 90° set square. The angle of measure 90° (i.e., a right angle) is common between them.

Question 4. Study the diagram. The line l is perpendicular to line m.

NCERT-Solutions-for-Class-6-Maths-Chapter-5-Understanding-Elementary-Shapes-21

(a) Is CE = EG?
(b) Does PE bisect CG?
(c) Identify two line segments for which PE is the perpendicular bisector.
(d) Are these true?
(i) AC > EG
(ii) CD = GH
(iii) BC < EH.

Solution:

(a) CE= CD + DE
= 1 + 1=2 units
EG = EF + FG
= 1 + 1=2 units
∴ CE= EG

(b) ∴ CE = EG
∴ E is the mid-point of CG.
∴ Line PE bisects line segment CG

(c) ∴ DE = EF = 1 unit
∴ PE is the perpendicular bisector of line segment DF
∴ BE = EH = 3 units
∴ PE is the perpendicular bisector of BH

(d)
(i)
 true
(ii) true
(iii) true

NCERT Solutions for Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.5 PDF

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Class 6 Maths Chapter 5 Understanding Elementary Shapes

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