NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4
Here, below you all know about NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4 Question Answer. I know many of you confuse about finding this Chapter 14 Practical Geometry Ex 14.4 Of Class 6 NCERT Solutions. So, Read the full post below and get your solutions.
| Textbook | NCERT |
| Board | CBSE |
| Category | NCERT Solutions |
| Class | Class 6 |
| Subject | Maths |
| Chapter | Chapter 14 |
| Chapter Name | Practical Geometry Ex 14.4 |
| Number of Questions Solved | 3 |
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4
NCERT TEXTBOOK EXERCISES
Question 1. Draw any line segment $\overline { AB }$. Mark any point M on it. Through M draw a perpendicular to $\overline { AB }$. (use ruler and compasses).
Solution :
Step 1. Given a point M on any line $\overline { AB }$.
Step 2. With M as centre and a convenient radius, construct a part circle (arc) intersecting the line segment $\overline { AB }$ at two points C and D.
Step 3. With C and D as centres and a radius greater than CM, construct two arcs which cut each other at N.
Step 4. Join $\overline { MN }$. Then $\overline { MN }$ is perpendicular to $\overline { AB }$ at M, i.e., $\overline { MN }$ $\overline { AB }$.
Question 2. Draw any’line segment $\overline { PQ }$. Take any point R not on it. Through R draw a perpendicular to $\overline { PQ }$. (use ruler and set-square).
Solution :
Step 1. Let $\overline { PQ }$ be the given line segment and R be a point not on it.
Step 2. Place a set-square on $\overline { PQ }$ such that one arm of the right angle aligns along $\overline { PQ }$.
Step 3. Place a ruler along the edge opposite of the right angle.
Step 4. Hold the ruler fixed. Slide the set-square along the ruler all the point R touches the arm of the set-square.
Step 5. Join RS along the edge through R, meeting $\overline { PQ }$ at S. Now $\overline { RS }$ $\overline { PQ }$.
Question 3. Draw a line l and a point X on it. Through X, draw a line segment $\overline { XY }$ perpendicular to l. Now draw a perpendicular to XY at Y. (use ruler and compasses)
Solution :
Step 1. Given a point X on a line l.
Step 2. With X as centre and a convenient radius, construct a part circle (arc) intersecting the line l at two points A and B.
Step 3. With A and B as centres and a radius greater than AX, construct two arcs which cut each other at Y.
Step 4. Join XY¯¯¯¯¯¯¯¯. Then XY¯¯¯¯¯¯¯¯ is perpendicular to l atX, i.e., XY¯¯¯¯¯¯¯¯ l.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4 PDF
For NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4, you may click on the link below and get your NCERT Solutions for Class 6 Maths Chapter 14 pdf file.
Finally, You all know about NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4. If you have any questions, then comment below and share this post with others.
Class 6 Maths Chapter 14 Practical Geometry
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.1
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.2
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.3
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.4
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.5
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.6
