NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2
Here, below you all know about NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 Question Answer. I know many of you confuse about finding this Chapter 14 Practical Geometry Ex 14.2 Of Class 6 NCERT Solutions. So, Read the full post below and get your solutions.
Textbook | NCERT |
Board | CBSE |
Category | NCERT Solutions |
Class | Class 6 |
Subject | Maths |
Chapter | Chapter 14 |
Chapter Name | Practical Geometry Ex 14.2 |
Number of Questions Solved | 6 |

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2
NCERT TEXTBOOK EXERCISES
Question 1. Draw a line segment of length 7.3 cm. using a ruler.
Solution :
Using ruler, we mark two points A and B which are 7.3 cm apart. Join A and B and get AB. $\overline { AB }$ is a line segment of length 7.3 cm.

Question 2. Construct a line segment of length 5.6 cm using ruler and compasses.

Solution :
Step 1. Draw a line l. Mak a point A on line l.
Step 2. Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto the 5.6 cm mark.
Step 3. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at B.
Step 4. AB is a line segment of required length.
Question 3. Construct $\overline { AB }$ of length 7.8 cm. From this cut off $\overline { AC }$ of length 4.7 cm. Measure $\overline { BC}$.
Solution :
Steps of Construction
Step 1. Draw a line l. Mark a point A on line l.
Step 2. Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto the 7.8 cm mark.

Step 3. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at B.
Step 4. $\overline { AB }$ is a line segment of length 7.8 cm.
Step 5. Place the compass pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto 4.7 cm mark.
Step 6. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at C.
Step 7. $\overline { AC }$ is a line segment of length 4.7 cm. On measurement. $\overline { BC }$ =3.1 cm.
Question 4. Given $\overline { AB }$ of length 3.9 cm, construct $\overline { PQ }$ such that the length of $\overline { PQ }$ is twice that of AB Verify by measurement.

(Hint : Construct $\overline { PX }$ such that length of PX = length of $\overline { AB }$; then cut off XQ¯¯¯¯¯¯¯¯ such that $\overline { XQ }$ also has the length of$\overline { AB }$).
Solution :
Steps of Construction
Step 1. Draw a line I. Mark a point P on line l.
Step 2. Place the compasses pointer on the A mark of the given line segment $\overline { AB }$. Open it to place the pencil point upto B mark of the given line segment $\overline { AB }$.

Step 3. Without changing the opening of the compasses, place the pointer on P and swing an arc to cut l at X.
Step 4. Again without changing the opening of the compasses place the compasses pointer on the X mark of line / and swing an arc to cut / at Q.
Step 5. $\overline { PQ }$ is a line segment of length twice that of $\overline { AB }$. Please verify yourself by measurement.
Question 5. Given $\overline { AB }$ of length 7.3 cm and $\overline { CD }$ of length 3.4 cm, construct a line segment $\overline { XY }$ such that the length of $\overline { XY }$ is equal to the difference between the lengths of $\overline { AB }$ and $\overline { CD }$. Verify by measurement.
Solution :
Steps of Construction
Step 1. Draw a line l. Mark a point X on line l.
Step 2. Place the compasses pointer on the A mark of the given line segment $\overline { AB }$. Open it to place the pencil point upto B mark of the given line segment $\overline { AB }$.
Step 3. Without changing the opening of the compasses, place the pointer of compasses on X and swing an arc to cut / at ∠.
Step 4. Place the compasses pointer on the C mark of the given line segment $\overline { CD }$. Open it to place the pencil point upto D mark of the given line segment $\overline { CD }$.
Step 5. Without changing the opening of the compasses, place the pointer of compasses on ∠ and swing an arc towards X to cut l at Y.
Step 6. $\overline { XY }$ is a required line segment of length = the difference between the lengths of $\overline { AB }$ and $\overline { CD }$.

Please verify yourself by measurement.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 PDF
For NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2, you may click on the link below and get your NCERT Solutions for Class 6 Maths Chapter 14 pdf file.
Finally, You all know about NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2. If you have any questions, then comment below and share this post with others.
Class 6 Maths Chapter 14 Practical Geometry
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.1
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.2
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.3
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.4
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.5
- Class 6 Maths Chapter 14 Practical Geometry Ex 14.6