# NCERT Solutions For Class 11 Maths Chapter 2 Relations and Functions Ex 2.3

Here, Below you all know about NCERT Solutions for Class 11 Maths Chapter 2 Relations and Functions Ex 2.3 Question Answer. I know many of you confuse about finding Chapter 2 Relations and Functions Ex 2.3 Of Class 11 NCERT Solutions. So, Read the full post below and get your solutions.

## NCERT Solutions for Class 11 Maths Chapter 2 Relations and Functions Ex 2.3

NCERT TEXTBOOK EXERCISES

Ex 2.3 Class 11 Maths Question 1. Which of the following relations are functions? Give reasons. If it is a function, determine its domain and range.

(i) {(2, 1), (5, 1), (8, 1), (11, 1), (14, 1), (17, 1)}
(ii) {{2, 1), (4, 2), (6, 3), (8, 4), (10, 5), (12, 6), (14, 7)}
(iii) {(1, 3), (1, 5), (2, 5)}.

Solution.

(i) We have a relation R = {(2, 1), (5, 1), (8, 1), (11, 1), (14, 1), (17, 1)} Since 2, 5, 8, 11, 14, 17 are the elements of domain of R having their unique images.
∴ The given relation is a function.
Hence domain = {2, 5, 8, 11, 14, 17) and Range = {1}.

(ii) We have a relation
R = {(2,1), (4, 2), (6, 3), (8, 4), (10, 5), (12, 6), (14, 7)}
Since 2, 4, 6, 8, 10, 12, 14 are the elements of domain of R having their unique images.
∴ The given relation is a function.
Hence domain = {2, 4, 6, 8, 10, 12, 14} and Range = {1, 2, 3, 4, 5, 6, 7}.

(iii) We have a relation R = {(1, 3), (1, 5), (2, 5)}
Since the distinct ordered pairs (1, 3) and (1, 5) have same first element i.e., 1 does not have a unique image under R.
∴ It is not a function.

Ex 2.3 Class 11 Maths Question 2. Find the domain and range of the following real functions:

(i) f(x) = −|x|
(ii) f(x) = $\sqrt { 9-{ x }^{ 2 } }$

Solution.

Ex 2.3 Class 11 Maths Question 3. A function f is defined by f (x) = 2x – 5. Write down the values of

(i) f (0)
(ii) f (7)
(iii) f (-3)

Solution.

We are given f (x) = 2x – 5
(i) f (0) = 2(0) – 5 = 0- 5 = -5
(ii) f (7) = 2(7) – 5 = 14- 5 = 9
(iii) f (-3) = 2(-3) – 5 = -6 – 5 = -11.

Ex 2.3 Class 11 Maths Question 4. The function T which maps temperature in degree Celsius into temperature in degree by $t(C)=\frac { 9C }{ 5 } +32$

Find
(i) t (0)
(ii) t (28)
(iii) t (-10)
(iv) The value of C, when t (C = 212

Solution.

Ex 2.3 Class 11 Maths Question 5. Find the range of each of the following functions.

(i) f(x) = 2 – 3x, x ∈ R, x>0.
(ii) f(x)=x2+ 2, x is a real number.
(iii) f (x) = x, x is a real number.

Solution.

(i) Given f (x) = 2 – 3x, x ∈ R, x > 0
∵ x > 0 ⇒ -3x < 0 ⇒ 2 – 3x < 2 + 0 ⇒ f (x) < 2
∴ The range of f (x) is (-2).

(ii) Given f (x) = x2 + 2, x is a real number
We know x2≥ 0 ⇒ x2 + 2 ≥ 0 + 2
⇒ x2 + 2 > 2 ∴ f (x) ≥ 2
∴ The range of f (x) is [2, ∞).

(iii) Given f (x) = x, x is a real number.
Let y =f (x) = x ⇒ y = x
∴ Range of f (x) = Domain of f (x)
∴ Range of f (x) is R.

## NCERT Solutions for Class 11 Maths Chapter 2 Relations and Functions Exercise 2.3 PDF

For NCERT Solutions for Class 11 Maths Chapter 2 Relations and Functions Ex 2.3, you may click on the link below and get your NCERT Solutions for Class 11 Maths Chapter 2 Relations and Functions Exercise pdf file.