# NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2

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Textbook | NCERT |

Board | CBSE |

Category | NCERT Solutions |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 8 |

Exercise | Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2 |

Number of Questions Solved | 4 |

## NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2

**NCERT TEXTBOOK EXERCISES**

**Class 10 Ex 8.2 Question 1. Evaluate the following:**

**Solution:**

**Ex 8.2 Class 10 Question 2. Choose the correct option and justify your choice:**

**Solution:**

**Exercise 8.2 Class 10 Question 3. If tan (A + B) = √3 and tan (A – B) = 1√3; 0° < A + B ≤ 90°; A > B, find A and B.**

**Solution:**

tan (A + B) = √3

⇒ tan (A + B) = tan 60°

⇒ A + B = 60° ……(i)

tan (A – B) = 1√3

⇒ tan (A – B) = tan 30°

⇒ A – B = 30° ……..(ii)

Adding equation (i) and (ii), we get

2A = 90° ⇒ A = 45°

From (i), 45° + B = 60° ⇒ B = 60° – 45° = 15°

Hence, ∠A = 45°, ∠B = 15°

**Exercise 8.2 Class 10 NCERT Solution Question 4. State whether the following statements are true or false. Justify your answer.**

(i) sin (A + B) = sin A + sin B.

(ii) The value of sin θ increases as θ increases.

(iii) The value of cos θ increases as θ increases.

(iv) sin θ = cos θ for all values of θ.

(v) cot A is not defined for A = 0°.

**Solution:**

## NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2 PDF

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