# NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2

Here, Below you all know about NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2 Question Answer. I know many of you confuse about finding Chapter 8 Introduction to Trigonometry Ex 8.2 Of Class 10 NCERT Solutions. So, Read the full post below and get your solutions.

## NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2

NCERT TEXTBOOK EXERCISES

Class 10 Ex 8.2 Question 1. Evaluate the following:

Solution:

Ex 8.2 Class 10 Question 2. Choose the correct option and justify your choice:

Solution:

Exercise 8.2 Class 10 Question 3. If tan (A + B) = √3 and tan (A – B) = 1√3; 0° < A + B ≤ 90°; A > B, find A and B.

Solution:

tan (A + B) = √3
⇒ tan (A + B) = tan 60°
⇒ A + B = 60° ……(i)
tan (A – B) = 1√3
⇒ tan (A – B) = tan 30°
⇒ A – B = 30° ……..(ii)
Adding equation (i) and (ii), we get
2A = 90° ⇒ A = 45°
From (i), 45° + B = 60° ⇒ B = 60° – 45° = 15°
Hence, ∠A = 45°, ∠B = 15°

Exercise 8.2 Class 10 NCERT Solution Question 4. State whether the following statements are true or false. Justify your answer.

(i) sin (A + B) = sin A + sin B.
(ii) The value of sin θ increases as θ increases.
(iii) The value of cos θ increases as θ increases.
(iv) sin θ = cos θ for all values of θ.
(v) cot A is not defined for A = 0°.

Solution:

## NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.2 PDF

For NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2, you may click on the link below and get your NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise pdf file.