# NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1

Here, Below you all know about NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 Question Answer. I know many of you confuse about finding Chapter 8 Introduction to Trigonometry Ex 8.1 Of Class 10 NCERT Solutions. So, Read the full post below and get your solutions.

## NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1

NCERT TEXTBOOK EXERCISES

Exercise 8.1 Class 10 Question 1. In ∆ABC right angled at B, AB = 24 cm, BC = 7 cm. Determine:

(i) sin A, cos A
(ii) sin C, cos C

Solution:

Class 10 Ex 8.1 Question 2. In given figure, find tan P – cot R.

Solution:

Trigonometry Class 10 Question 3. If sin A = 3/4 , calculate cos A and tan A.

Solution:

sin A = 3/4
sin A = BC/AC = sin A = 3/4
Let BC = 3k and AC = 4k

Ex 8.1 Class 10 Question 4. Given 15 cot A = 8, find sin A and sec A.

Solution:

Class 10 Trigonometry Ex 8.1 Question 5. Given sec θ = 13/12 , calculate all other trigonometric ratios.

Solution:

Ex 8.1 Class 10 Question 6. If ∠A and ∠B are acute angles such that cos A = cos B, then show that ∠A = ∠B.

Solution:

Ex 8.1 Class 10 Question 7. If cot θ = 7/8, evaluate:

(i) $\frac { \left( 1+sin\theta \right) \left( 1-sin\theta \right) }{ \left( 1+cos\theta \right) \left( 1-cos\theta \right)}$
(ii) cot²θ

Solution:

Trigonometry NCERT Class 10 Ex 8.1 Question 8. If 3 cot A = 4, check whether $\frac { 1-tan^{ 2 }A }{ 1+tan^{ 2 }A }$ = cos² A – sin² A or not.

Solution:

Ex 8.1 Class 10 Maths Solutions Question 9. In triangle ABC, right angled at B, if tan A = 1/√3, find the value of:

(i) sin A cos C + cos A sin C
(ii) cos A cos C – sin A sin C

Solution:

Class 10 Ex 8.1 Question 10. In ΔPQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.

Solution:

NCERT Solutions For Class 10 Maths Chapter 8 Question 11. State whether the following statements are true or false. Justify your answer.

(i) The value of tan A is always less than 1.
(ii) sec A = 12/5 for some value of angle A.
(iii) cos A is the abbreviation used for the cosecant of angle A.
(iv) cot A is the product of cot and A.
(v) sin θ = 4/3 for some angle.

Solution:

(i) tan 60° = √3 , Since √3 > 1. (False)
(ii) sec A is always ≥ 1. (True)
(iii) cos A is the abbreviation for cosine A. (False)
(iv) cot without ∠A is meaningless. (False)
(v) sin θ can never be greater than 1.
∴ sin θ = P/H , hypotenuse is always greater than other two sides. (False)

## NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.1 PDF

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