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NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex 6.4

Here, Below you all know about NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.4 Question Answer. I know many of you confuse about finding Chapter 6 Triangles Ex 6.4 Of Class 10 NCERT Solutions. So, Read the full post below and get your solutions.

TextbookNCERT
BoardCBSE
CategoryNCERT Solutions
ClassClass 10
SubjectMaths
ChapterChapter 6
ExerciseClass 10 Maths Chapter 6 Triangles Exercise 6.4
Number of Questions Solved9
NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex 6.4

NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.4

NCERT TEXTBOOK EXERCISES

Question 1. Let ∆ABC ~ ∆DEF and their areas be, respectively, 64 cm2 and 121 cm2. If EF = 15.4 cm, find BC.

Solution:

Since, ∆ABC ~ ∆DEF
The ratio of the areas of two similar triangles is equal to the ratio of the squares of the corresponding sides.

Question 2. Diagonals of a trapezium ABCD with AB || DC intersect each other at the point O. If AB = 2 CD, find the ratio of the areas of triangles AOB and COD.

Solution:

ABCD is a trapezium with AB || DC and AB = 2 CD

Question 3. In the given figure, ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, show that

Solution:

Question 4. If the areas of two similar triangles are equal, prove that they are congruent.

Solution:

Question 5. D, E and F are respectively the mid-points of sides AB, BC and CA of ∆ABC. Find the ratio of the areas of ∆DEF and ∆ABC.

Solution:

Question 6. Prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians.

Solution:

Question 7. Prove that the area of an equilateral triangle described on one side of a square is equal to half the area of the equilateral triangle described on one of its diagonals.

Solution:

Question 8. ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Ratio of the areas of triangles ABC and BDE is

(a) 2 :1
(b) 1:2
(c) 4 :1
(d) 1:4

Solution:

Question 9. Sides of two similar triangles are in the ratio 4:9. Areas of these triangles are in the ratio

(a) 2:3
(b) 4:9
(c) 81:16
(d) 16:81

Solution:

Justification: Areas of two similar triangles are in the ratio of the squares of their corresponding sides.

NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.4 PDF

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