# NCERT Solutions For Class 10 Maths Chapter 11 Constructions Ex 11.2

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Textbook | NCERT |

Board | CBSE |

Category | NCERT Solutions |

Class | Class 10 |

Subject | Maths |

Chapter | Chapter 11 |

Exercise | Class 10 Maths Chapter 11 Constructions Exercise 11.2 |

Number of Questions Solved | 7 |

## NCERT Solutions for Class 10 Maths Chapter 11 Constructions Ex 11.2

**NCERT TEXTBOOK EXERCISES**

**Question 1. Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pair of tangents to the circle and measure their lengths.**

**Solution:**

**Steps of Construction:**1. Draw a circle of radius 6 cm.

2. Mark a point P at a distance 10 cm from the centre O.

3. Here OP = 10 cm, draw perpendicular bisector of OP, which intersects OP at O’.

4. Take O’ as centre, draw a circle of radius O’O, which passes through O and P and intersects the previous circle at points T and Q.

5. Join PT and PQ, measure them, these are the required tangents.

**Justification:**

Join OT and OQ

A pair of tangents can be drawn to a circle from an external point outside the circle. These two tangents are equal in lengths.

∴ PT = PQ.

**Question 2. Construct a tangent to a circle of radius 4 cm from a point on the concentric circle of radius 6 cm and measure its length. Also verify the measurement by actual calculation.**

**Solution:**

**Steps of Construction:**

1. Draw concentric circles of radius OA = 4 cm and OP = 6 cm having same centre O.

2. Mark these circles as C and C’.

3. Points O, A and P lie on the same line.

4. Draw perpendicular bisector of OP, which intersects OP at O’.

5. Take O’ as centre, draw a circle of radius OO’ which intersects the circle C at points T and Q.

6. Join PT and PQ, these are the required tangents.

7. Length of these tangents are approx. 4.5 cm.

**Justification:**

Join OT and OQ.

A pair of tangents can be drawn to a circle from an external point outside the circle. These two tangents are equal in lengths.

∴ PT = PQ.

**Question 3. Draw a circle of radius 3 cm. Take two points P and Q on one of its extended diameter each at a distance of 7 cm from its centre. Draw tangents to the circle from these two points P and Q.**

**Solution:**

**Steps of Construction:**

1. Draw a circle of radius 3 cm, having centre O. Mark this circle as C.

2. Mark points P and Q along its extended diameter such that OP = 7 cm and OQ = 7 cm.

3. Draw perpendicular bisector of OQ, intersecting OQ at O’.

4. Draw perpendicular bisector of OP intersecting OP at O”.

5. Take O’ as centre and draw a circle of radius OO’ which passes through points O and Q, intersecting circle C at points R and T.

6. Take O” as centre and draw a circle of radius O”P which passes through points O and P, intersecting the, circle C at points S and U.

7. Join QR and QT; PS and PU, these are the required tangents.

**Justification:**

Join OR.

In ∆OQR,

OR ⊥ QR [Radius ± to tangent]

OQ^{2} = OR^{2} + QR^{2}

⇒ (7)^{2} = (3)^{2} + QR^{2} ⇒ 49 = 9 + OR^{2}

⇒ 40 = QR^{2} ⇒ QR = 2 √10 cm

Similary,

QT = 2 √10 cm

PS = 2 √10 cm

PU = 2 √10 cm

A pair of tangents can be drawn to a circle from an external point outside the circle. These two tangents are equal in lengths.

∴ QR = QT and PS = PU

**Question 4. Draw a pair of tangents to a circle of radius 5 cm which are inclined to each other at an angle of 60°.**

**Solution:**

**Steps of Construction:**

1. Draw a circle of radius 5 cm.

2. As tangents are inclined to each other at an angle of 60°.

∴ Angle between the radii of circle is 120°. (Use quadrilateral property)

3. Draw radii OA and OB inclined to each other at an angle 120°.

4. At points A and B, draw 90° angles. The arms of these angles intersect at point P.

5. PA and PB are the required tangents.

**Justification:**

In quadrilateral AOBP,

AP and BP are the tangents to the circle.

Join OP.

In right angled AOAP, OA ⊥ PA [Radius is ⊥ to tangent]

A pair of tangents can be drawn to a circle from an external point outside the circle. These two tangents are equal in lengths.

∴ PA = PB

**Question 5. Draw a line segment AB of length 8 cm. Taking A as centre, draw a circle of radius 4 cm and taking B as centre, draw another circle of radius 3 cm. Construct tangents to each circle from the centre of the other circle.**

**Solution:**

**Steps of Construction:**

1. Draw a line segment AB = 8 cm.

2. Taking A as centre draw a circle C of radius 4 cm and taking B as centre draw a circle C’ of radius 3 cm.

3. Draw perpendicular bisector of AB, which intersects AB at point O.

4. Taking point O as centre draw a circle of radius 4 cm passing through points A and B which intersect circle C at P and S and circle C’ at points R and Q.

5. Join AQ, AR, BP and BS. These are the required tangents.

**Justification:**

Join AP.

A pair of tangents can be drawn to a circle from an external point outside the circle. These two tangents are equal in lengths.

∴ AQ = AR and BP = BS.

**Question 6. Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and ZB = 90°. BD is the perpendicular Burn B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.**

**Solution:**

**Steps of Construction:**

1. Draw a right triangle ABC with AB = 6 cm, BC = 8 cm and ZB = 90°.

2. From B, draw BD perpendicular to AC.

3. Draw perpendicular bisector of BC which intersect BC at point O’.

4. Take O’ as centre and O’B as radius, draw a circle C’ passes through points B, C and D.

5. Join O’A and draw perpendicular bisector of O’A which intersect O’A at point K.

6. Take K as centre, draw an arc of radius KO’ intersect the previous circle C’ at T.

7. Join AT, AT is required tangent.

**Justification:**

∠BDC = 90°

∴ BC acts as diameter.

AB is tangent to circle having centre O’

A pair of tangents can be drawn to a circle from an external point outside the circle. These two tangents are equal in lengths.

∴ AB = AT.

**Question 7. Draw a circle with the help of a bangle. Take a point outside the circle. Construct the pair of tangents from this point to the circle.**

**Solution:**

**Steps of Construction:**

1. Draw a circle C’ with the help of a bangle, for finding the centre, take three non-collinear points A, B and C, lying on the circle. Join AB and BC and draw perpendicular bisector of AB and BC, both intersect at a point O,

‘O’ is centre of the circle.

2. Take a point P outside the circle. Join OP.

3. Draw perpendicular bisector of OP, which intersects OP at point O’.

4. Take O’ as the centre with OO’ as radius draw a circle which passes through O and P, intersecting previous circle C’ at points R and Q.

5. Join PQ and PR.

6. PQ and PR are the required pair of tangents.

**Justification:**

Join OQ and OR.

In AOQP and AOPR, OQ = OR [Radii of the circle]

OP = OP [Common]

∠Q = ∠R = 90° [Radius is ⊥ to tangent]

∆OQP ≅ ∆ORP [by RHS]

∴ PQ = PR [By C.P.C.T]

A pair of tangents can be drawn to a circle from an external point lying outside the circle. These two tangents are equal in lengths.

∴ PQ = PR

## NCERT Solutions for Class 10 Maths Chapter 11 Constructions Exercise 11.2 PDF

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